Question

What is the maximum speed that a car can maneuver over a circular turn of radius r = 75.0 m without sliding if the coefficient of static friction is µs = 0.780? (b) What is the maximum speed that a car can maneuver over a circular turn of radius r = 25.0 m without sliding if the coefficient of static friction is µs = 0.120?

Answer 1

Step-by-step explanation:

Given

Radius of Track
`r_1=75 m`

coefficient of Static Friction
`\mu _s=0.78`

Here centripetal Force is Balanced by Friction Force

thus

`(mv^2)/(r)=\mu _sg`

`(v^2)/(r)=\mu _sg`

`v=√(\mu _srg)`

`v=√(0.78* 75* 9.8)`

`v=23.94 m/s`

(b)For
`r_2=25 m`

`\mu _s=0.12`

`v=√(\mu _sr_2g)`

`v=√(0.12* 25* 9.8)`

`v=5.42 m/s`