Question

Add the following
-3a2b2, (–5/2) a2b2, 4a2b2, and (⅔) a2b2​

Answer 1

Given:

The terms are
`-3a^2b^2,-(5)/(2)a^2b^2,4a^2b^2,(2)/(3)a^2b^2`.

To find:

The sum of given terms.

Solution:

Sum of given terms is

`-3a^2b^2+(-(5)/(2)a^2b^2)+4a^2b^2+(2)/(3)a^2b^2`

`=-3a^2b^2-(5)/(2)a^2b^2+4a^2b^2+(2)/(3)a^2b^2`

Taking out common factors, we get

`=\left(-3-(5)/(2)+4+(2)/(3)\right)a^2b^2`

`=\left((-18-15+24+4)/(6)\right)a^2b^2`

`=\left((-5)/(6)\right)a^2b^2`

`=(-5)/(6)a^2b^2`

Therefore, the sum of given terms is
`(-5)/(6)a^2b^2`.