Question

A Car goes from rest to a velocity of 108 m/s north in 10s whats the cars acceleration in m/s²​

Answer 1

answer

Step-by-step explanation:

the law is :

a=vf-vi on t

vi=0

vf=108 m/s

t=10/s

108 - 0 on 10 = 10.8

Answer 2

the acceleration of the car is 10.8 m/s².

Step-by-step explanation:

Initial velocity (u) = 0

Final velocity (v) = 108 m/s

time (t) = 10 sec

Acceleration(a) = ?

we know

a = (v-u) / t

= 108 / 10

= 10.8 m/s²