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5 votes
Write an equation of the line that passes through the points
(0, 3) and (-5, 0).

2 Answers

5 votes

Answer:

y-3=3/5x

Explanation:

y-y1=m(x-x1)

Where m=slope and (x1, y1) is a point on the line.

m=(y2-y1)/(x2-x1)

m=(0-3)/(-5-0)

m=-3/-5

m=3/5

y-3=3/5(x-0)

y-3=3/5(x)

y-3=3/5x

User Diogo Aleixo
by
8.0k points
3 votes

(0, 3) is the y-intercept as it passes through y = 3 at x = 0, or the y-axis.

Slope:


(y1 - y0)/(x1 - x0) = (3 - 0)/(0 - ( - 5)) = (3)/(5)

Equation of a straight line:

y = mx + c

m = slope (3/5)

c = y value of y-intercept (3)

Equation:


y = (3)/(5) x + 3

User Francesc VE
by
7.4k points

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