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A thermodynamic system undergoes a process in which its internal energy decreases by 1,477 J. If at the same time 678 J of thermal energy is transferred to it, how much work (in J) is done by the system?

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Answer:2155 J

Step-by-step explanation:

Given

Change in Internal energy
\Delta U=-1477 J i.e. decrease in Internal Energy

Heat added to system
Q=678 J

According First law for a system


dQ=dU+dW


678=-1477+dW


dW=2155 J

Thus 2155 J of work is done by system

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