Question

PLEASE HURRY!!

Two hot air balloons are traveling along the same path away from a town,
beginning from different locations at the same time. Henry's balloon begins
30 miles from the town and is 48 miles from the town after 2 hours. The
distance of Tasha's balloon from the town is represented by the function y =
8x+ 20.
Whích balloon was farther from the town at the beginning, and which traveled
more quickly?
O
A. Tasha's balloon was farther from the town at the beginning, but
Henry's balloon traveled more quickly.
O
B. Tasha's balloon was farther from the town at the beginning, and it
traveled more quickly.
O
C. Henry's balloon was farther from the town at the beginning, but
Tasha's balloon traveled more quickly.
O
D. Henry's balloon was farther from the town at the beginning, and it
traveled more quickly.​

Answer 1

Henry's balloon was farther from the town at the beginning, but Tasha's balloon traveled more quickly.

Step-by-step explanation:

To determine which balloon was farther from the town at the beginning, we need to compare the initial distances of Henry's and Tasha's balloons from the town. Henry's balloon begins 30 miles from the town, while Tasha's balloon is represented by the function y = 8x + 20, where x is the time in hours. Plugging in x = 0 into the function, we can find that Tasha's balloon was 20 miles from the town at the beginning.

To determine which balloon traveled more quickly, we can compare their speeds. Henry's balloon travels at a constant speed of (48 miles - 30 miles) / 2 hours = 9 miles/hour. Tasha's balloon has a constant speed of 8 miles/hour since it follows the equation y = 8x + 20. Therefore, Henry's balloon traveled more quickly.

Therefore, the correct answer is OC. Henry's balloon was farther from the town at the beginning, but Tasha's balloon traveled more quickly.

Answer 2

a.

Step-by-step explanation: