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A hand pump is being used to inflate a bicycle tire that has a gauge pressure of 59.0 lb/in2. If the pump is a cylinder of length 17.4 in. with a cross-sectional area of 3.00 in.2, how far down must the piston be pushed before air will flow into the tire? Assume the temperature is constant.

Answer must be in inches

User MagicKat
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1 Answer

6 votes

Answer:

∴The air cannot be made to flow in with the given pump at the given conditions.

Step-by-step explanation:

Given:

  • gauge pressure of bicycle tyre,
    P_g=59\ lb.in^(-2)
  • length of cylinder of the pump,
    l=17.4\ in
  • area of the the cylinder of the pump,
    a= 3\ in^2
  • we have the density of air at STP,
    \rho=4.4256* 10^(-5)\ lb.in^(-2)

The piston must be pushed more than the pressure inside the tyre:


P_g=\rho* V/ a


59=4.4256* 10^(-5)* a* h/ a


h=13.33* 10^5\ in

∴The air cannot be made to flow in with the given pump at the given conditions.

User Jesse Eichar
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