Question

Calculate the amount of CuSO4•5H2O required to make 25 mL of a 0.45 M solution of CuSO4.

Answer 1

Mass = 1.76 g

Step-by-step explanation:

Given data:

Volume of solution = 25 mL

Molarity = 0.45 M

Amount of CuSO₄.5H₂O = ?

Solution:

Molarity = number of moles / volume in litter

Number of moles = Molarity × Volume in L

Number of moles = 0.45 M × 0.025 L

Number of moles = 0.011 mol

Mass of f CuSO₄.5H₂O:

Mass = Number of moles × molar mass

Mass = 0.011 mol × 159.6 g/mol

Mass = 1.76 g