Question

Bi undergoes four decay reactions: α, β, β, α. Step 1. undergoes α decay to give In the second step, Tl-210 undergoes β decay. What is the product of this step? symbol = mass number = atomic number =

Answer 1

Pb-210 that lead-210 is the product of second step.

Step-by-step explanation:

Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.

General representation of alpha decay :

`_Z^A\textrm{X}\rightarrow _(Z-2)^(A-4)Y+_2^4\alpha`

Beta decay : In this process, a neutron is converted into a proton and an electron. In this decay, the atomic number is increased by 1 unit.

General representation of beta decay :

`_Z^A\textrm{X}\rightarrow _(Z+1)^(A)Y+_(-1)^0e`

Step 1. Bi undergoes α decay;

`_Z^A\textrm{X}\rightarrow _(81)^(210)Tl+_2^4\alpha`

81 = Z-2

Z = 83

210 = A - 4

A = 214

`_(83)^(214)\textrm{X}\rightarrow _(81)^(210)Tl+_2^4\alpha`

Step 2: Tl-210 undergoes β decay:

`_(81)^(210)\textrm{X}\rightarrow _(82)^(210)Pb+_(-1)^0e`

Pb-210 that lead-210 is the product of second step.