150 different committees are possible
Solution:
Given that a student dance committee is to be formed consisting of 2 boys and 4 girls
The membership is to be chosen from 5 boys and 6 girls
To find : number of different possible committees
A combination is a selection of all or part of a set of objects, without regard to the order in which objects are selected
The formula for combination is given as:
![n C_(r)=(n !)/((n-r) ! r !)](https://img.qammunity.org/2020/formulas/mathematics/high-school/jbozimwhxbz1757s3tvfyzt5kyx7arhnxc.png)
where "n" represents the total number of items, and "r" represents the number of items being chosen at a time
We have to select 2 boys from 5 boys
So here n = 5 and r = 2
![\begin{aligned} 5 C_(2) &=(5 !)/((5-2) ! 2 !)=(5 !)/(3 ! 2 !) \\\\ 5 C_(2) &=(5 * 4 * 3 * 2 * 1)/(3 * 2 * 1 * 2 * 1) \\\\ 5 C_(2) &=10 \end{aligned}](https://img.qammunity.org/2020/formulas/mathematics/high-school/k4lfban5a01gjprgoy7eg9sv04j5nwov6c.png)
We have to select 4 girls from 6 girls
Here n = 6 and r = 4
![\begin{aligned} 6 C_(4) &=(6 !)/((6-4) ! 4 !)=(6 !)/(2 ! 4 !) \\\\ 6 C_(4) &=(6 * 5 * 4 * 3 * 2 * 1)/(2 * 1 * 4 * 3 * 2 * 1)=15 \end{aligned}](https://img.qammunity.org/2020/formulas/mathematics/high-school/wmlifalob0gst38q8shngrzavl6g8ifvbw.png)
Committee is to be formed consisting of 2 boys and 4 girls:
So we have to multiply
and
![6 C_(4)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ecamtwqdwx35q2skitlsvvdbxink6qjto8.png)
![5 C_(2) * 6 C_(4)=10 * 15=150](https://img.qammunity.org/2020/formulas/mathematics/high-school/a4j7xungopsjwx2b2rv9m6e2ayhise4elo.png)
So 150 different committees are possible