147k views
1 vote
An event sold $608 worth of tickets. Adult tickets cost $11 and children's tickets cost $6. If 68 tickets were sold, how many were adult tickets and how many were children's tickets?

2 Answers

4 votes
Alright so what I got is 54 adults and 1 kid
User Robert Sheahan
by
7.7k points
5 votes

Answer: There were 40 adult tickets and 28 children's tickets

Explanation:

Let x represent the number of adult tickets sold.

Let y represent the number of children's tickets sold.

An event sold $608 worth of tickets adult tickets cost $11 while children's tickets cost $6. It means that

11x + 6y = 608 - - - - - - 1

If 68 tickets were sold, it means that

x + y = 68

Substituting x = 68 - y into equation 1, it becomes

11(68 - y) + 6y = 608

748 - 11y + 6y = 608

- 11y + 6y = 608 - 748

- 5y = 140

y = 140/5 = 28

x = 68 - y = 68 - 28

x = 40

User Karl Lopez
by
6.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.