Question

In NMR if a chemical shift(δ) is 211.5 ppm from the tetramethylsilane (TMS) standard and the spectrometer frequency is 556 MHz, how many Hz from TMS is the signal at? Give at least three significant figures.

Answer 1

The answer is: 11759 Hz

Step-by-step explanation:

Given: Chemical shift: δ = 211.5 ppm, Spectrometer frequency = 556 MHz = 556 × 10⁶ Hz

In NMR spectroscopy, the chemical shift (δ), expressed in ppm, of a given nucleus is given by the equation:

`\delta (ppm) = (Observed\,frequency (Hz))/(Frequency\,\, of\,\,the\,Spectrometer (MHz)) * 10^(6)`

`\therefore Observed\,frequency (Hz)= (\delta (ppm)* Frequency\,\, of\,\,the\,Spectrometer (MHz))/(10^(6))`

`Observed\,frequency= (211.5 ppm * 556 * 10^(6) Hz)/(10^(6)) = 11759 Hz`

Therefore, the signal is at 11759 Hz from the TMS.