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A coin is tossed 10 times. True or false, and explain: (a) The chance of getting 10 heads in a row is 1/1,024. (b) Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is 1/2.

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Answer:

a and b both are true.

Explanation:

Given : A coin is tossed 10 times.

To find : True or false, and explain ?

Solution :

(a) The chance of getting 10 heads in a row is
(1)/(1024)

Coin has two face head and tail.

The probability of getting head is
P(H)=(1)/(2)

The probability of getting 10 heads in a row is


P=(P(H))^(10)


P=((1)/(2))^(10)


P=(1)/(1024)

The chance of getting 10 heads in a row is
(1)/(1024) is true.

(b) Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is
(1)/(2).

The probability of getting 10 heads in a row is
P_1=((1)/(2))^(10)

The probability of getting 9 tosses were heads is
P_2=((1)/(2))^(9)

Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is given by,


P=(P_1)/(P_2)


P=(((1)/(2))^(10))/(((1)/(2))^(9))


P=((1)/(2))^(10-9)


P=(1)/(2)

Given that the first 9 tosses were heads, the chance of getting 10 heads in a row is
(1)/(2) is true.

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