Question

A chemistry student needs 10.0 mL of acetone for an experiment. By consulting the CRC Handbook of Chemistry and Physics, the student discovers that the density of acetone is 0.790 g cm .

Calculate the mass of acetone the student should weigh out. Be sure your answer has the correct number of significant digits.

Answer 1

To find the mass of acetone needed for the experiment, the student multiplies the density of acetone (0.790 g/mL) by the required volume (10.0 mL) to get 7.90 g, considering significant figures.

Step-by-step explanation:

The student needs to calculate the mass of acetone required for their experiment. Given that the density of acetone is 0.790 g/cm³ (which is equivalent to 0.790 g/mL since 1 cm³ is equal to 1 mL), and the volume needed is 10.0 mL, they can use the formula density = mass/volume to find the mass.

To find the mass, the student should rearrange the formula to mass = density × volume. Using the given values, the calculation is as follows:

mass = 0.790 g/mL × 10.0 mL = 7.90 g

Therefore, the student should weigh out 7.90 g of acetone for their experiment, making sure to use the correct number of significant digits as provided in the question.

Answer 2

The student has to weigh 7.9 ±0.1 grams

Step-by-step explanation:

Density of acetone : 0.790 g/cm³

If the student has to measure 10.0 mL of acetone, he can weigh an specific mass.

Density of acetone = Mass of acetone / Volume of acetone

cm³ = mL

0.790 g/cm³ = Mass of acetone / 10 cm³

0.790 g/cm³ . 10cm³ = 7.9 g