Answer:
Time taken to accelerate to 48 m/s = 8 seconds
Step-by-step explanation:
Initially the object is moving south at =
![16 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/1f4ml92oreonkig722ea4zmhydm0dgxj5p.png)
So, initial velocity of the object =
![16 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/1f4ml92oreonkig722ea4zmhydm0dgxj5p.png)
Acceleration caused by the force = 4
![m/s^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v7ag5o4aueq1b2v8zb82ds7o60bu03pzmc.png)
Final velocity towards south =
![48 m/s](https://img.qammunity.org/2020/formulas/physics/high-school/bl967f9756sa9hmuruso2e8p76tiur520u.png)
Using equation of motions:
![v_f=v_i+at](https://img.qammunity.org/2020/formulas/physics/high-school/a7pz7jzwwe0jmw5t54s9v1j1u594g0z22r.png)
where
final velocity
initial velocity
acceleration
time
Plugging in values.
![48=16+(4)t](https://img.qammunity.org/2020/formulas/physics/high-school/pv0hzjcwgvku5fbos2un33aaouwyf52sh1.png)
![48=16+4t](https://img.qammunity.org/2020/formulas/physics/high-school/ne9pojl9fvm0oqtkc0a8y65qsl7b7970tq.png)
Subtracting both sides by 16
![48-16=16+4t-16](https://img.qammunity.org/2020/formulas/physics/high-school/4y1g9csxsai5rn148yd0hrd8y1m41k3zx6.png)
![32=4t](https://img.qammunity.org/2020/formulas/physics/high-school/xlagh2ebdf38374jyajw51e6gj5e24ed3v.png)
Dividing both side by 4.
![(32)/(4)=(4t)/(4)](https://img.qammunity.org/2020/formulas/physics/high-school/yt68dwct1pysuc32k7a39e99iola4t1e1n.png)
![8=t](https://img.qammunity.org/2020/formulas/physics/high-school/44t0y4u1gk1y3a6iwcc32k3qu33ygbf3ja.png)
∴
![t=8](https://img.qammunity.org/2020/formulas/mathematics/high-school/4o06qic19z44q3f8zvu7pvo1tj9iun7opo.png)
Time taken to accelerate to 48 m/s = 8 seconds