Question

What is the initial drag force for a golf ball with the following conditions? Frontal area: 14 cm2 (remember to convert to m2), air density: 1.204 kg/m3, initial velocity: 50 m/s, coefficient of drag: 0.3

Answer 1

F= 0.6321 N

Step-by-step explanation:

Given

Area ,A= 14 cm²

Density ,ρ = 1.204 kg/m³

Velocity ,v= 50 m/s

Drag coefficient ,C=0.3

The drag force on the golf given as

`F=(1)/(2)\rho CAv^2`

Now by putting the values

`F=(1)/(2)\rho CAv^2`

`F=(1)/(2)* 0.3* 1.204 * (14* 10^(-4))* 50^2\ N`

F= 0.6321 N

Therefore force due to drag on the golf is 0.6321 N