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What is 4th root 7 cubed
in exponential form? Edge

User SrThompson
by
8.5k points

1 Answer

8 votes

Answer:


\displaystyle \sqrt[4]{7^3}=7^{(3)/(4)}

Explanation:

Exponential Form of Radicals

A radical of the form


\displaystyle \sqrt[n]{x^m}

Can be expressed in exponential form as follows:


\displaystyle \sqrt[n]{x^m}=x^{(m)/(n)}

We are given the number 4th root of 7 cubed. Writing in radical form:


\displaystyle \sqrt[4]{7^3}

It can be expressed in exponential form as:


\boxed{\displaystyle \sqrt[4]{7^3}=7^{(3)/(4)}}

User Benoitr
by
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