Question

Calculate the phase angle (in radians) for a circuit with a maximum voltage of 12 V and w-50 Hz. The voltage source is connected in series with a 20e-2 F capacitor, a 20-mH inductor, and a 50- resistor. -1.37 radians 0.134 radians 0.0180 radians 0.0300 radians

Answer 1

The phase angle is 0.0180 rad.

(c) is correct option.

Step-by-step explanation:

Given that,

Voltage = 12 V

Angular velocity = 50 Hz

Capacitance
`C= 20*10^(-2)\ F`

Inductance
`L=20*10^(-3)\ H`

Resistance
`R=  50\ Omega`

We need to calculate the impedance

Using formula of impedance

`z=\sqrt{R^2+(\omega L-(1)/(\omega C))^2}`

`z=\sqrt{50^2+(50*20*10^(-3)-(1)/(50*20*10^(-2)))^2}`

`z=50.00`

We need to calculate the phase angle

Using formula of phase angle

`\theta=\cos^(-1)((R)/(z))`

`\theta=\cos^(-1)((50)/(50.00))`

`\theta=0.0180\ rad`

Hence, The phase angle is 0.0180 rad.