Question

The pressures of 2000 is exerted On a force of 15 and find area​

Answer 1

• P=2000Pa
• F=15N

`\\ \rm\longmapsto P=(F)/(A)`

`\\ \rm\longmapsto A=(F)/(P)`

`\\ \rm\longmapsto A=(15)/(2000)`

`\\ \rm\longmapsto A=0.007m^2`

Answer 2

Given that,

Pressure, P = 2000 Pa

Force, F = 15 N

To find,

The area of the cross section.

Solution,

We know that,

Pressure = force/area

or

`P=(F)/(A)\\\\A=(F)/(P)\\\\A=(15)/(2000)\\\\=0.0075\ m^2\\\\=75\ cm^2`

So, the area of cross section is
`75\ cm^2`.