Question

he drag characteristics of a torpedo are to be studied in a water tunnel using a 1 : 7 scale model. The tunnel operates with freshwater at 20 ˚C, whereas the prototype torpedo is to be used in seawater at 15.6 ˚C. To correctly simulate the behavior of the prototype moving with a velocity of 53 m/s, what velocity is required in the water tunnel?

Answer 1

Answer:20.03 m/s

Step-by-step explanation:

Given

`L_r=1:7`

velocity of Prototype
`v_p=53 m/s`

Taking Froude number same for both flow as it is a dimensionless number for different flow regimes in open Flow

`((v_m)/(√(L_mg)))=((v_p)/(√(L_pg)))`

`v_m=v_p* \sqrt{(L_m)/(L_p)}`

`v_m=53* (1)/(√(7))`

`v_m=20.03 m/s`