Question

A circular copper disk of diameter D=10 cm rotates at frequency =1800 rev/min about an axis through its center and at right angles to the disk. A uniform magnetic field B of 10,000 gauss is perpendicular to the disk. What potential difference e develops between the axis of the disk and its rim?

Answer 1

e=2356.125 V

Step-by-step explanation:

Given that

D= 10 cm = 0.1 m

R= 0.05

B= 10,000

Angular speed ,ω = 1800 rev/min

Speed in rad/s given as

`\omega =(2\pi N)/(60)`

`\omega =(2\pi * 1800)/(60)`

ω= 188.49 rad/s

The potential difference given as

e= B R v

v=average speed

`v=(\omega)/(2)R`

`e=(B)/(2)R^2 {\omega}`

By putting the values

`e=(10000)/(2)0.05^2 * {188.49}`

e=2356.125 V