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A gas sample enclosed in a rigid metal container at room temperature (20.0∘C) has an absolute pressure p1. The container is immersed in hot water until it warms to 40.0∘C. What is the new absolute pressure p2?

User Grigorevp
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2 Answers

6 votes

Final answer:

The question is from the domain of Physics, where it deals with the behavior of gases subjected to temperature changes, as per Gay-Lussac's Law. It can be solved using the formula P1/T1 = P2/T2 after converting Celsius to Kelvin.

Step-by-step explanation:

The subject of this question is Physics, and it is suitable for students at the High School level. The question deals with the concept of gases and their behavior when subjected to changes in temperature, specifically within the context of the ideal gas law and Gay-Lussac's Law, which states that the pressure of a gas is directly proportional to its temperature when the volume is held constant. To find the new absolute pressure p2 after the gas is heated from 20.0°C to 40.0°C in a rigid container, we can use Gay-Lussac's Law in the form of P1/T1 = P2/T2, assuming the amount of gas and the volume remains constant. Since temperatures must be in Kelvin for gas law calculations, they will be converted first: T1 = 293.15 K and T2 = 313.15 K. The new pressure p2 can then be calculated by multiplying p1 by the ratio of T2 to T1.

User Cheri
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5 votes

Answer:

it is 60.0° C

Step-by-step explanation:

that is the new pressure p2

User Rahul Dadhich
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