Answer:
a and f (Tortoise shell females and black males).
Step-by-step explanation:
Let black fur colour allele be AA, orange will be aa and tortoiseshell will be Aa. Since the trait is X-linked;
- Black female will be
![X^(A) X^(A)](https://img.qammunity.org/2020/formulas/biology/high-school/ph8ecrvil343axp5ajvk5b018lf7c34pgz.png)
- Orange male will be
(Y chromosome is assumed to not carry any trait, hence, the male can either be black or orange, they can never be heterozygote)
Crossing
x
![X^(a)Y](https://img.qammunity.org/2020/formulas/biology/college/u80lzlulvozspvg31fvj5yzojrlyo0gtt5.png)
Progeny:
,
,
,
![X^(A)Y](https://img.qammunity.org/2020/formulas/biology/college/bwetkhi20knnns7xgmgps73t1ft7n0nf5y.png)
- Two heterozygote/tortoiseshell fur colour females
- Two black males
The correct answer is a and f.