Answer:
Average rowing velocity of boat in still water is 4 miles per hour and average velocity of the current is 1 mile per hour.
Explanation:
We are given the following in the question:
Let x be the average rowing velocity of boat in still water and y be the the average velocity of the current.

The boat rowed 7.5 miles downstream, with the current, in 1.5 hours.
Velocity with the current =

Thus, we can write the equation:

The return trip upstream, against the current, covered the same distance, but took 2.5 hours.
Velocity against the current =

Thus, we can write the equation:

Solving, the two equations:

Thus, average rowing velocity of boat in still water is 4 miles per hour and average velocity of the current is 1 mile per hour.