Question

Water is boiling in an aluminum pan placed on an electrical element on a stovetop. The pan has a bottom that is 0.800 cm thick and 14.0 cm in diameter. Aluminum thermal conductivity is 220 W/(m oC). In every second, 1.2 g boiling water evaporates. The latent heat of vaporization for water is 2.26 × 106 J/kg. (a) How much heat is transfered to the boiling water in one second?

Answer 1

Step-by-step explanation:

The given data is as follows.

Thickness = 0.8 cm =
`0.8 * 10^(-3) m` (As 1 m = 1000 cm)

Diameter = 14.0 cm, Conductivity =
`220 W/(m^(o)C)`

mass = 1.2 g, L =
`2.26 * 10^(6) J/kg`

Now, we will calculate the heat of vaporization for water as follows.

Q = mL

Q =
`0.8 * 10^(-3) * 2.26 * 10^(6)`

Q = 1808 J

So, rate of heat transfer in 1 sec will be as follows.

`(Q)/(t)` = 1808 J/s

Thus, we can conclude that 1808 J/s heat is transfered to the boiling water in one second.