Question

Four point charges are placed at the corners of a square. Each charge has the identical value +Q. The length of the diagonal of the square is 2a.

What is the electric potential at the center of the square?

Answer 1

Answer:
`V_(net)=4(kQ)/(a)`

Step-by-step explanation:

Given

charge on each Particle is Q

Length of diagonal of the square is 2a

therefore distance between center and each charge is
`(2a)/(2)=a`

Electric Potential of charged Particle is given by

For First Charge

`V_1=(kQ)/(a)`

`V_2=(kQ)/(a)`

`V_3=(kQ)/(a)`

`V_4=(kQ)/(a)`

total Electric Potential At center is given by

`V_(net)=V_1+V_2+V_3+V_4`

`V_(net)=4* (kQ)/(a)`

`V_(net)=4(kQ)/(a)`