Answer:
The area of the given figure is
.
Explanation:
To find out the area we should have to redraw the figure having nomenclature ABCDE and join BD. Thus we have a rectangle ABDE and a triangle BCD.
The new figure is in the attachment.
Given,
Length of AE = 7 cm
Length of DE = 8 cm
Length of CF = 11 cm
Solution,
Area of rectangle ABDE =
![length* breadth=length\ of AE*length\ of DE](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ajg6jpbc0baugale7cf7hjp19qgz16w9hk.png)
Area of ABDE =
![7*8=56\ cm^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b1yaqj4m0rqilfmx415la2skshqm3ydech.png)
Now for triangle BCD,
Length of BD = length of AE = 7 cm
Length of GF = Length of DE = 8 cm
∴ Length of CG = Length of CF-Length of GF =
![11-8=3\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fzwqny2xrk43xawxnvbajykylbor42hm4i.png)
Area of triangle BCD =
![(1)/(2)* base* height}=(1)/(2)* length\ of\ BD* length\ of\ GF](https://img.qammunity.org/2020/formulas/mathematics/middle-school/de3a0v9ll8k9jxvtk2qdzrvt761iqvyeo4.png)
Area of BCD =
![(1)/(2)*7*3=(21)/(2)=10.5\ cm^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6473d1xf0jteiimpatrz9uaamv82zw2lhc.png)
Area of ABCDE = Area of ABDE + Area of BCD =
![56+10.5=66.5\ cm^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kvug9xw1n5bvyssr9psf4wo82c55kr7isj.png)
Thus the area of the given figure is
.