Question

Two plates are 2cm apart, a potential difference of 10 V is applied

between them, find the electric field between the plates.

Answer 1

The electric field betwee the plates is 500 V/m

Step-by-step explanation:

Voltage

The electrical potential difference V between the two plates is expressed as

V=Ed

Where:

E = Electric field strength

d = Distance between the plates

It's expressed in Joules/coulomb, Volts/m or equivalent units.

The plates are separated d=2 cm and a potential difference V=10 V is applied. The electric field strength between the plates can be calculated by solving the formula for E:

`\displaystyle E=(V)/(d)`

Converting cm to m: d=2 / 100 = 0.02 m

`\displaystyle E=(10\ V)/(0.02\ m)`

Dividing:

E = 500 V/m

The electric field betwee the plates is 500 V/m