Question

a plane flies from Addis Ababa to Gamble is 400km. in 2 hrs, then straight back to Gamma is 200km. in 1hrs what is the average speed, average velocity, total distance and total displacement​

Answer 1

a) Average speed = 200 Km/hr

b) Average velocity = 0 m/s

c) Total distance = 800 Km

d) Total displacement = 0 Km

Step-by-step explanation:

a) Let the speed of the plane from Addis Ababa to Gamble be represented by
`S_(1)`, and from Gamble to Addis Ababa by
`S_(2)`.

Average speed =
`(S_(1) + S_(2) )/(2)`

`S_(1)` =
`(distance)/(time)` =
`(400)/(2)`

= 200 Km/hr

`S_(2)` =
`(distance)/(time)` =
`(200)/(1)`

= 200 Km/hr

Average speed =
`(200 + 200)/(2)`

= 200 Km/hr

b) Velocity =
`(displacement)/(time)`

Average velocity =
`(total displacement)/(total time taken)`

Since the plane flies from Addis Ababa to Gamble, then back to Addis Ababa, its total displacement is zero.

So that,

Average velocity = 0 m/s

c) Total distance = 400 Km + 400 Km

= 800 Km

d) Total displacement = 400 Km + (-400 Km)

= 0 Km