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The uniform crate has a mass of 150 kg. The coefficient of static friction between the crate and the floor is μs = 0.2. The coefficient of static friction between the man's shoes and the floor is μ′s = 0.4. Assume the man only exerts a horizontal force on the crate. Determine whether the 85-kg man can move the crate.

User Josh Morel
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Answer:

The man will be able to move the crate.

Step-by-step explanation:


\mu_s = Coefficient of static friction between the crate and the floor = 0.2


\mu'_s = Coefficient of static friction between the man's shoes and the floor = 0.4


m_c = Mass of crate = 150 kg


m_p = Mass of man = 85 kg

g = Acceleration due to gravity = 9.81 m/s²

Horizontal force in order to move the crate is given by


F_h=\mu_sm_cg\\\Rightarrow F_h=0.2* 150* 9.81\\\Rightarrow F_h=294.3\ N

Maximum force that the man can apply


F_m=\mu'_sm_pg\\\Rightarrow F_m=0.4* 85* 9.81\\\Rightarrow F_m=333.54\ N

Here it can be seen that
F_m>F_h.

So, the man will be able to move the crate.

User Betti
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