Question

A compound microscope is made with an objective lens (f0 = 0.900 cm) and an eyepiece (fe = 1.10 cm). The lenses are separated by a distance of 10.0 cm. What is the angular magnification? (Assume the near point is 25.0 cm.)

Answer 1

-252.52

Step-by-step explanation:

L = Distance between lenses = 10 cm

D = Near point = 25 cm

`f_o` = Focal length of objective = 0.9 cm

`f_e` = Focal length of eyepiece = 1.1 cm

Magnification of a compound microscope is given by

`m=-(L)/(f_o)(D)/(f_e)\\\Rightarrow m=-(10)/(0.9)* (25)/(1.1)\\\Rightarrow m=-252.52`

The angular magnification of the compound microscope is -252.52