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A bicycle wheel of radius 0.70 m is rolling without slipping on a horizontal surface with an angular speed of 2.0 rev/s when the cyclist begins to uniformly apply the brakes. The bicycle stops in 5.0 s. Through how many revolutions did the wheel rotate during the 5.0 seconds of braking?

User Bazooka
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1 Answer

3 votes

Answer:

θ= 5 radian

Step-by-step explanation:

Given data:

Radius r = 0.70 m

Initial angular speed ω_i = 2rev/s

Time t = 5 s

Final angular speed ω_f =0

so we have angular displacement


\theta= (\omega_f-\omega_i)/(2)* t

putting values


\theta= (0-2)/(2)*5 = 5 rad

User Rajeev Sahu
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