Question

The buoyant force on a ball of weight W, dropped in a container of water is F. If the same ball is dropped into a container of liquid with half the density of water, the buoyant force on the ball will be

Answer 1

Answer:
`(F)/(2)`

Step-by-step explanation:

Given

weight of Object is W

Buoyant Force
`F_b=F`

let the density of First Liquid is
`\rho`

volume of object
`=(W)/(\rho _0g)`

where
`\rho _0`=object density

thus buoyant Force in first Liquid is

`F=\rho * (W)/(\rho _0g)* g=(W\rho )/(\rho _0)`

For Second Liquid

`F'=(\rho )/(2)* (W)/(\rho _0g)* g=(W\rho )/(2\rho _0)`

`F'=(F)/(2)`