Answer:
494.24 W
442.41 W
51.83 W
Step-by-step explanation:
A = Area of person = 1.2 m²
= Person's temperature = 27+273.15 = 300.15 K
= Room temperature = 18.8+273.15 = 291.95 K
= Emissivity of skin = 0.895
= Stefan-Boltzmann constant =

Radiated power of the person

Power radiated by the person is 494.24 W
Radiated power absorbed by the person

Radiated power absorbed by the person is 442.41 W
Net power would be

The net power loss is 51.83 W