Question

A large spherical tank contains gas at a pressure of 400 psi. The tank is constructed of high-strength steel having a yield stress in tension of 80 ksi. For volume requirements, the inner diameter of the tank is 45-ft. Determine the required thickness (to the nearest ¼ inch) of the wall of the tank if a factor of safety of 3.0 with respect to yielding is required.

Answer 1

t=2.025 inches

Step-by-step explanation:

Given that

P = 400 Psi

Yield stress ,σ = 80 ksi

Diameter ,d= 45 ft

We know that

1 ft = 12 inches

d= 540 inches

Factor of safety ,K= 3

The required thickness given as

`\frac {Pd}{4t}=(\sigma)/(K)`

t=thickness

`\frac {PdK}{4\sigma}=t`

`\frac {400* 540* 3}{4* 80* 1000}=t`

t=2.025 inches

Therefore thickness will be 2.025 inches.