Answer:
a) 6.3 minutes
Explanation:
Population mean (μ) = 7.2 minutes
Standard deviation (σ) = 0.56 minutes
The z-score for any running time 'X' is given by:
In this scenario, the company is looking for the top 5% runners, that is, runners at and below the 5-th percentile of the normal distribution. The equivalent z-score for the 5-th percentile is 1.645.
Therefore, the minimum speed, X, a runner needs to achieve in order to be sponsored is:
![-1.645=(X-7.2)/(0.56)\\X= 6.3\ minutes](https://img.qammunity.org/2020/formulas/mathematics/college/yoy595svdkc9f03radcnkrksel0rxew0qc.png)