Question

Help pls................

Answer 1

x = - 10, x = 10

Explanation:

Given

- 7 +
`(x^2-19)^{(3)/(4) }` = 20 ( add 7 to both sides )

`(x^2-19)^{(3)/(4) }` = 27 , that is

`\sqrt[4]{(x^2-19)^(3) }` = 27 ( raise both sides to the power of 4 )

(x² - 19)³ =
`27^(4)` = 531441 ( take the cube root of both sides )

x² - 19 =
`\sqrt[3]{531441}` = 81 ( add 19 to both sides )

x² = 100 ( take the square root of both sides )

x = ±
`√(100)` = ± 10

solution is x = - 10, x = 10

Answer 2

Hai!!! Your answer is both x=-10 and x=10