Answer:
The slope intercept of the given line equation AB is
![y = (1)/(2) ( x)- (5)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uwcb1i0r31ttbq110h9931o9uqn7zj36n6.png)
Explanation:
Here,the two given point s are A ( -9,-2) and B (1,3).
Now, the slope m of the line AB =
![= (y_2 - y_1)/(x_2 -x_1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qezto71im4ze3tutz2wey83rpt4d7lkqmc.png)
![\implies m = (3 - (-2))/(1 - (-9)) = (3+2)/(1+9) = (5)/(10) = (1)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2za57fm4iz905y6ml1msuhx4nqwhzn2x4o.png)
or, the slope of line AB = 1/2
Now, the POINT SLOPE FORM of any equation with point (x0,y0) and slope m is given as :
y - y0 = m (x -x0)
So, the line equation of AB is given as :
![y - 3 = (1)/(2) ( x-1)\\\implies y =3 + (1)/(2) ( x-1)\\or, y = (1)/(2) ( x)- (5)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/c3qa0esjs3lqxbh8dua1lvu5rn25rhjghs.png)
SLOPE INTERCEPT form is y = mx + c
Hence, the slope intercept of the given line equation AB is
![y = (1)/(2) ( x)- (5)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uwcb1i0r31ttbq110h9931o9uqn7zj36n6.png)