Question

3 When Klorina swims with the current, she swims 10 km

In 2 h. Against the current, she can swim only 8 km in
the same time. How fast can Klorina swim in still water?
What is the rate of the current?

Answer 1

Speed in still water
`=` 9km

Speed of the current
`=` 1 km

Answer:

Explanation:

Speed of the current
`=` C

Speed of the still water
`=` S

Speed with the current
`=`
`(` speed of the still water ₊ speed of the current
`)`

`=` S ₊ C

Speed with the current
`=` S ₊ C
`=` 10km

Speed against the current
`=`
`(` speed of the still water ₋speed of the current
`)`

`=` S ₋ C

Speed against the current
`=` S ₋ C
`=` 8km

Speed in still water
`=` Speed with the current ₊ Speed against the current
`)`÷ 2

`= (` 10 ₊ 8
`)` ÷ 2

`=`
`(` 18
`)` ÷ 2

Speed in still water
`=` 9km

Speed of the current
`= (` Speed with the current ₋ Speed against the current
`)` ÷ 2

`= (` 10 ₋ 8
`)` ÷ 2

`=`
`(` 2
`)` ÷ 2

Speed of the current
`=` 1 km