For this case we have that by definition, the equation of the line in the slope-intersection form is given by:
![y = mx + b](https://img.qammunity.org/2020/formulas/mathematics/high-school/fc4cgm6covys37zv2opmmp9ps4jxyjepvh.png)
Where:
m: It is the slope of the line
b: It is the cut-off point with the y axis
We have two points through which the line passes:
![(x_ {1}, y_ {1}) :( 8,5)\\(x_ {2}, y_ {2}): (- 6,5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bhek0pka5piwjag1y10dlh7ypw6ncem46g.png)
We found the slope:
![m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {5-5} {- 6-8} = \frac {0} {- 14} = 0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wnv7pgs9v2vo1dk8ags5fqxivqhbtvgx9j.png)
The slope is zero.
Thus, the equation is of the form:
![y = b](https://img.qammunity.org/2020/formulas/mathematics/middle-school/fvdbuzupsae49m3tk9e6uor906zwcpb7ok.png)
We substitute one of the points and find b:
![(x, y) :( 8,5)\\5 = b\\b = 5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s6k0f37ajkmvrlxvmbbl1regvxqy315jty.png)
Finally, the equation is:
![y = 5](https://img.qammunity.org/2020/formulas/mathematics/high-school/8dt98xb4fsifqnbjarhlzg529e5h26o45a.png)
Answer:
![y = 5](https://img.qammunity.org/2020/formulas/mathematics/high-school/8dt98xb4fsifqnbjarhlzg529e5h26o45a.png)