Question

Pls help me need to submit on sir quick

Answer 1

x = 3.83

y = 0.84

Explanation:

Given;

`(2)/(x-3y) = 1(1)/(2) ((5)/(x+y) ) ---(i)\\\\3x -5y = 7---(ii)\\`

Solving the simultaneous equation by elimination method;

`(2)/(x-3y) = (3)/(2) ((5)/(x+y) )\\\\(2)/(x-3y) =(15)/(2x+2y) \\\\15(x-3y) = 2(2x +2y)\\\\15x - 45y = 4x + 4y\\\\11x - 49y = 0 --(i)\\\\3x - 5y = 7 --(ii)\\\\3: \ \ 33x -147= 0 ---(iii)\\\\11: -(33x -55y =77) ---(iv)\\{-----------} \\ (iii\ + \ iv): -92y = -77\\\\y = (77)/(92) = 0.84 \\\\solve \ for \ x \ using \ (ii)\\\\3x - 5((77)/(92) ) = 7\\\\3x - (385)/(92) = 7\\\\3x = 7 + (385)/(92)\\\\3x = (644 + 385)/(92) \\\\3x = (1029)/(92) \\\\`

`3x = (1029)/(92) \\\\x = (1029)/(92 * 3)\\\\x = 3.73`

(ii) By substitution method;

`11x - 49y = 0 --(i)\\\\3x - 5y = 7 --(ii)\\\\from \ (i), 11x = 49y\\\\x = (49y)/(11) \\\\substitute \ x \ in (ii);\\\\3((49y)/(11) ) - 5y = 7 \\\\(147y)/(11) - 5y = 7\\\\(147y - 55y)/(11)= 7\\\\92y = 77\\\\y = (77)/(92) = 0.84 \\\\solve \ for \ x;\\\\x = (49)/(11) ((77)/(92) ) = 3.73`