Answer: Yes, this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood.
Explanation:
Since we have given n = 157
x = 86
So,
![\hat{p}=(x)/(n)=(86)/(157)=0.55](https://img.qammunity.org/2020/formulas/mathematics/college/iaw9iupstj6x4kbk5xnv40f5f4ioo3rk7i.png)
and we have p = 0.4
So, hypothesis would be
![H_0:p=\hat{p}\\\\H_a:p\\eq \hat{p}](https://img.qammunity.org/2020/formulas/mathematics/high-school/jqvg0xc3qqu3l4xbb7i584uy0g4x1up2oq.png)
Since there is 1% level of significance.
So, test statistic value would be
![z=\frac{\hat{p}-p}{\sqrt{(p(1-p))/(n)}}\\\\z=\frac{0.55-0.40}{\sqrt{(0.4* 0.6)/(157)}}\\\\z=(0.15)/(0.039)\\\\z=3.846](https://img.qammunity.org/2020/formulas/mathematics/college/qst7n8oenh7m8r7pzzz49axad18q23tsad.png)
and the critical value at 1% level of significance , z = 2.58
Since 2.58<3.846.
So, we reject the null hypothesis.
Hence, Yes, this suggest that the actual percentage of type A donations differs from 40%, the percentage of the population having type A blood.