Question

(2x^3+6x-1)+(3x^2-7x)

Answer 1

For this case we must simplify the following expression:

`(2x ^ 3 + 6x-1) + (3x ^ 2-7x)`

We eliminate the parentheses taking into account that:

`+ * + = +\\+ * - = -`

So, we have:

`2x ^ 3 + 6x-1 + 3x ^ 2-7x =`

We add similar terms taking into account that:

Different signs are subtracted and the sign of the major is placed:

`2x ^ 3 + 3x^2-x-1`

Answer:

`2x ^ 3 + 3x^2-x-1`