Answer:
0.958 m
Step-by-step explanation:
So the total mass of the system is
M = 1.93 + 2.95 + 2.41 + 3.99 = 11.28 kg
let y be the distance from the center of mass to the origin. With the reference to the origin then we have the following equation
![My = m_1y_1 + m_2y_2 +m_3y_3 + m_4y_4](https://img.qammunity.org/2020/formulas/physics/college/42tka8ocobf0p8il3mtw3t5gfgc7p22v32.png)
![11.28y = 1.93*2.91 + 2.95*2.43 + 2.41*0 + 3.99*(-0.496) = 10.806](https://img.qammunity.org/2020/formulas/physics/college/ftrubwq5ix3rl5d14a0dmld345tloym8t0.png)
![y = (10.806)/(11.28) = 0.958 m](https://img.qammunity.org/2020/formulas/physics/college/br3zs4ejjmlccc3ezybrc8n1w77b0gwn4m.png)
So the center of mass is 0.958 m from the origin