Question

A rectangular parking lot has a perimeter of 384 meters. The length of the parking lot is 36 meters less than the width. Find the length and the width.

Answer 1

The length and width of the parking lot is 78 meters and 114 meters respectively.

Explanation:

Given;

Perimeter of the parking lot =
`384\ m`

Solution,

Let the width of the parking lot be x.

Then, according to question length = (x-36).

The perimeter of a rectangle is sum of all the sides of rectangle. Which is given by an expression;

`perimeter=2*(length+width)`

Now substituting the values, we get;

`384=2*(x-36+x)\\(384)/(2)=(2x-36)\\192=2x-36\\192+36=2x\\2x=228\\x=(228)/(2)= 114`

Width =
`114\ m`

Length =
`x-36=114-36=78\ m`

Hence the length and width of the parking lot is 78 meters and 114 meters respectively.