Question

3x - 3y = -3
2x - y = -5​

Answer 1

For this case we must solve the following system of equations:

`3x-3y = -3\\2x-y = -5`

To solve we follow the steps below:

We multiply the second equation by -3:

`-6x + 3y = 15`

Thus, we have the equivalent system:

`3x-3y = -3\\-6x + 3y = 15`

We add the equations:

`3x-6x-3y + 3y = -3 + 15\\-3x = -3 + 15\\-3x = 12\\x = \frac {12} {- 3}\\x = -4`

We look for the value of the variable "y":

`2 (-4) -y = -5\\-8-y = -5\\-y = -5 + 8\\-y = 3\\y = -3`

Thus, the solution of the system is given by:

`(x, y): (- 4, -3)`

Answer:

`(x, y): (- 4, -3)`