Answer:
s=29.93m/s
h=22.88m
Explanation:
we must find the initial speed, we will determine its position (x-y).
x component

y component
since the ball is caught at the same height then h=0

where t= flight time;
, replacing t:

![s=v_(0)cos\alpha((2sin\alpha )/(g))=(v_(0) ^(2)2sin\alpha.cos\alpha)/(g)=(v_(0) ^(2)sin(2\alpha))/(g)]</p><p>: the values must be taken to the same units</p><p></p><p>[tex]300ft*0.3048m/ft=91.44m]()

To calculate the height you should know that this is achieved when its component at y = 0

replacing t;

finally
