Question

8. If I have 34 grams of FeO, how many grams of Oxygen were synthesized?
Fe + O2 → Feo​

Answer 1

34 gram of FeO produced 8 gram of oxygen.

Step-by-step explanation:

Given data:

Mass of FeO = 34 g

Mass of oxygen = ?

Solution;

Chemical equation:

2FeO → 2Fe + O₂

Number of moles of FeO:

Number of moles = mass/ molar mass

Number of moles = 34 g /71.8 g/mol

Number of moles = 0.5 mol

Now we will compare the moles of FeO with oxygen:

FeO : O₂

2 : 1

0.5 : 1/2 × 0.5 = 0.25

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.25 mol × 32 g/mol

Mass = 8 g

So 34 gram of FeO produced 8 gram of oxygen.