Question

A box with a frontal area of 2.5 ft2 and with a drag coefficient of CD =0.9 is fastened on the roof of your car. What is the aerodynamic drag force in pounds due to the box alone at a velocity of 88 ft/sec?

Answer 1

To solve this problem it is necessary to apply the concepts related to the drag force.

By definition we know that drag force can be expressed as

`F_D = (1)/(2) \rho C_D AV^2`

Where,

\rho = Density

`C_D =`Drag Coefficient

A = Area

V = Velocity

Our values are given as

`A = 2.5ft^2`

`V = 88ft/s`

`C_D = 0.9`

`\rho = 0.0765lb/ft^3 \rightarrow` Air at normal temperature

Replacing at the equation we have,

`F_D = (1)/(2) \rho C_D AV^2`

`F_D = (1)/(2) (0.0765lb/ft^3) (0.9) (2.5ft^2) (88ft/s)^2`

`F_D = 666.468lbf`

The aerodynamic drag force is 666.468Lbf