Question

I NEED HELP PLEASE. LOOK AT PICTURE

Answer 1

Part 1)
`(a^4)/(4b^2)`

Part 2)
`-(v^9)/(w^6)`

Explanation:

we know that

When divide exponents (or powers) with the same base, subtract the exponents

Part 1) we have

`(3a^(2)b^(-4))/(12a^(-2)b^(-2))=((3)/(12))(a^(2+2))(b^(-4+2) )=(1)/(4)a^(4)b^(-2)=(a^4)/(4b^2)`

Part 2) we have

`(v^3w^(-3))/(-v^(-6) w^3) =-v^(3+6)w^(-3-3)=-v^9w^(-6)=-(v^9)/(w^6)`